Optimal. Leaf size=494 \[ \frac{\left (-a^2 b^2 (61 A-3 C)+a^4 (8 A-21 C)+35 A b^4\right ) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{12 a^3 d \left (a^2-b^2\right )^2}+\frac{b \left (-a^2 b^2 (65 A-3 C)+3 a^4 (8 A-3 C)+35 A b^4\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{4 a^4 d \left (a^2-b^2\right )^2}+\frac{\left (3 a^4 b^2 (21 A-2 C)-a^2 b^4 (86 A-3 C)+15 a^6 C+35 A b^6\right ) \Pi \left (\frac{2 b}{a+b};\left .\frac{1}{2} (c+d x)\right |2\right )}{4 a^4 d (a-b)^2 (a+b)^3}-\frac{\left (-a^2 b^2 (13 A+C)-5 a^4 C+7 A b^4\right ) \sin (c+d x)}{4 a^2 d \left (a^2-b^2\right )^2 \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))}+\frac{\left (-a^2 b^2 (61 A-3 C)+a^4 (8 A-21 C)+35 A b^4\right ) \sin (c+d x)}{12 a^3 d \left (a^2-b^2\right )^2 \cos ^{\frac{3}{2}}(c+d x)}+\frac{\left (a^2 C+A b^2\right ) \sin (c+d x)}{2 a d \left (a^2-b^2\right ) \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))^2}-\frac{b \left (-a^2 b^2 (65 A-3 C)+3 a^4 (8 A-3 C)+35 A b^4\right ) \sin (c+d x)}{4 a^4 d \left (a^2-b^2\right )^2 \sqrt{\cos (c+d x)}} \]
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Rubi [A] time = 2.09596, antiderivative size = 494, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {3056, 3055, 3059, 2639, 3002, 2641, 2805} \[ \frac{\left (-a^2 b^2 (61 A-3 C)+a^4 (8 A-21 C)+35 A b^4\right ) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{12 a^3 d \left (a^2-b^2\right )^2}+\frac{b \left (-a^2 b^2 (65 A-3 C)+3 a^4 (8 A-3 C)+35 A b^4\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{4 a^4 d \left (a^2-b^2\right )^2}+\frac{\left (3 a^4 b^2 (21 A-2 C)-a^2 b^4 (86 A-3 C)+15 a^6 C+35 A b^6\right ) \Pi \left (\frac{2 b}{a+b};\left .\frac{1}{2} (c+d x)\right |2\right )}{4 a^4 d (a-b)^2 (a+b)^3}-\frac{\left (-a^2 b^2 (13 A+C)-5 a^4 C+7 A b^4\right ) \sin (c+d x)}{4 a^2 d \left (a^2-b^2\right )^2 \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))}+\frac{\left (-a^2 b^2 (61 A-3 C)+a^4 (8 A-21 C)+35 A b^4\right ) \sin (c+d x)}{12 a^3 d \left (a^2-b^2\right )^2 \cos ^{\frac{3}{2}}(c+d x)}+\frac{\left (a^2 C+A b^2\right ) \sin (c+d x)}{2 a d \left (a^2-b^2\right ) \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))^2}-\frac{b \left (-a^2 b^2 (65 A-3 C)+3 a^4 (8 A-3 C)+35 A b^4\right ) \sin (c+d x)}{4 a^4 d \left (a^2-b^2\right )^2 \sqrt{\cos (c+d x)}} \]
Antiderivative was successfully verified.
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Rule 3056
Rule 3055
Rule 3059
Rule 2639
Rule 3002
Rule 2641
Rule 2805
Rubi steps
\begin{align*} \int \frac{A+C \cos ^2(c+d x)}{\cos ^{\frac{5}{2}}(c+d x) (a+b \cos (c+d x))^3} \, dx &=\frac{\left (A b^2+a^2 C\right ) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))^2}+\frac{\int \frac{\frac{1}{2} \left (-7 A b^2+a^2 (4 A-3 C)\right )-2 a b (A+C) \cos (c+d x)+\frac{5}{2} \left (A b^2+a^2 C\right ) \cos ^2(c+d x)}{\cos ^{\frac{5}{2}}(c+d x) (a+b \cos (c+d x))^2} \, dx}{2 a \left (a^2-b^2\right )}\\ &=\frac{\left (A b^2+a^2 C\right ) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))^2}-\frac{\left (7 A b^4-5 a^4 C-a^2 b^2 (13 A+C)\right ) \sin (c+d x)}{4 a^2 \left (a^2-b^2\right )^2 d \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))}+\frac{\int \frac{\frac{1}{4} \left (35 A b^4+a^4 (8 A-21 C)-a^2 b^2 (61 A-3 C)\right )+a b \left (A b^2-a^2 (4 A+3 C)\right ) \cos (c+d x)-\frac{3}{4} \left (7 A b^4-5 a^4 C-a^2 b^2 (13 A+C)\right ) \cos ^2(c+d x)}{\cos ^{\frac{5}{2}}(c+d x) (a+b \cos (c+d x))} \, dx}{2 a^2 \left (a^2-b^2\right )^2}\\ &=\frac{\left (35 A b^4+a^4 (8 A-21 C)-a^2 b^2 (61 A-3 C)\right ) \sin (c+d x)}{12 a^3 \left (a^2-b^2\right )^2 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{\left (A b^2+a^2 C\right ) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))^2}-\frac{\left (7 A b^4-5 a^4 C-a^2 b^2 (13 A+C)\right ) \sin (c+d x)}{4 a^2 \left (a^2-b^2\right )^2 d \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))}+\frac{\int \frac{-\frac{3}{8} b \left (35 A b^4+3 a^4 (8 A-3 C)-a^2 b^2 (65 A-3 C)\right )-\frac{1}{2} a \left (7 A b^4-2 a^4 (A+3 C)-a^2 b^2 (14 A+3 C)\right ) \cos (c+d x)+\frac{1}{8} b \left (35 A b^4+a^4 (8 A-21 C)-a^2 b^2 (61 A-3 C)\right ) \cos ^2(c+d x)}{\cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))} \, dx}{3 a^3 \left (a^2-b^2\right )^2}\\ &=\frac{\left (35 A b^4+a^4 (8 A-21 C)-a^2 b^2 (61 A-3 C)\right ) \sin (c+d x)}{12 a^3 \left (a^2-b^2\right )^2 d \cos ^{\frac{3}{2}}(c+d x)}-\frac{b \left (35 A b^4+3 a^4 (8 A-3 C)-a^2 b^2 (65 A-3 C)\right ) \sin (c+d x)}{4 a^4 \left (a^2-b^2\right )^2 d \sqrt{\cos (c+d x)}}+\frac{\left (A b^2+a^2 C\right ) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))^2}-\frac{\left (7 A b^4-5 a^4 C-a^2 b^2 (13 A+C)\right ) \sin (c+d x)}{4 a^2 \left (a^2-b^2\right )^2 d \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))}+\frac{2 \int \frac{\frac{1}{16} \left (105 A b^6+a^4 b^2 (128 A-15 C)-a^2 b^4 (223 A-9 C)+8 a^6 (A+3 C)\right )+\frac{1}{4} a b \left (35 A b^4+4 a^4 (5 A-3 C)-a^2 b^2 (64 A-3 C)\right ) \cos (c+d x)+\frac{3}{16} b^2 \left (35 A b^4+3 a^4 (8 A-3 C)-a^2 b^2 (65 A-3 C)\right ) \cos ^2(c+d x)}{\sqrt{\cos (c+d x)} (a+b \cos (c+d x))} \, dx}{3 a^4 \left (a^2-b^2\right )^2}\\ &=\frac{\left (35 A b^4+a^4 (8 A-21 C)-a^2 b^2 (61 A-3 C)\right ) \sin (c+d x)}{12 a^3 \left (a^2-b^2\right )^2 d \cos ^{\frac{3}{2}}(c+d x)}-\frac{b \left (35 A b^4+3 a^4 (8 A-3 C)-a^2 b^2 (65 A-3 C)\right ) \sin (c+d x)}{4 a^4 \left (a^2-b^2\right )^2 d \sqrt{\cos (c+d x)}}+\frac{\left (A b^2+a^2 C\right ) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))^2}-\frac{\left (7 A b^4-5 a^4 C-a^2 b^2 (13 A+C)\right ) \sin (c+d x)}{4 a^2 \left (a^2-b^2\right )^2 d \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))}-\frac{2 \int \frac{-\frac{1}{16} b \left (105 A b^6+a^4 b^2 (128 A-15 C)-a^2 b^4 (223 A-9 C)+8 a^6 (A+3 C)\right )-\frac{1}{16} a b^2 \left (35 A b^4+a^4 (8 A-21 C)-a^2 b^2 (61 A-3 C)\right ) \cos (c+d x)}{\sqrt{\cos (c+d x)} (a+b \cos (c+d x))} \, dx}{3 a^4 b \left (a^2-b^2\right )^2}+\frac{\left (b \left (35 A b^4+3 a^4 (8 A-3 C)-a^2 b^2 (65 A-3 C)\right )\right ) \int \sqrt{\cos (c+d x)} \, dx}{8 a^4 \left (a^2-b^2\right )^2}\\ &=\frac{b \left (35 A b^4+3 a^4 (8 A-3 C)-a^2 b^2 (65 A-3 C)\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{4 a^4 \left (a^2-b^2\right )^2 d}+\frac{\left (35 A b^4+a^4 (8 A-21 C)-a^2 b^2 (61 A-3 C)\right ) \sin (c+d x)}{12 a^3 \left (a^2-b^2\right )^2 d \cos ^{\frac{3}{2}}(c+d x)}-\frac{b \left (35 A b^4+3 a^4 (8 A-3 C)-a^2 b^2 (65 A-3 C)\right ) \sin (c+d x)}{4 a^4 \left (a^2-b^2\right )^2 d \sqrt{\cos (c+d x)}}+\frac{\left (A b^2+a^2 C\right ) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))^2}-\frac{\left (7 A b^4-5 a^4 C-a^2 b^2 (13 A+C)\right ) \sin (c+d x)}{4 a^2 \left (a^2-b^2\right )^2 d \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))}+\frac{\left (35 A b^4+a^4 (8 A-21 C)-a^2 b^2 (61 A-3 C)\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx}{24 a^3 \left (a^2-b^2\right )^2}+\frac{\left (35 A b^6-a^2 b^4 (86 A-3 C)+3 a^4 b^2 (21 A-2 C)+15 a^6 C\right ) \int \frac{1}{\sqrt{\cos (c+d x)} (a+b \cos (c+d x))} \, dx}{8 a^4 \left (a^2-b^2\right )^2}\\ &=\frac{b \left (35 A b^4+3 a^4 (8 A-3 C)-a^2 b^2 (65 A-3 C)\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{4 a^4 \left (a^2-b^2\right )^2 d}+\frac{\left (35 A b^4+a^4 (8 A-21 C)-a^2 b^2 (61 A-3 C)\right ) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{12 a^3 \left (a^2-b^2\right )^2 d}+\frac{\left (35 A b^6-a^2 b^4 (86 A-3 C)+3 a^4 b^2 (21 A-2 C)+15 a^6 C\right ) \Pi \left (\frac{2 b}{a+b};\left .\frac{1}{2} (c+d x)\right |2\right )}{4 a^4 (a-b)^2 (a+b)^3 d}+\frac{\left (35 A b^4+a^4 (8 A-21 C)-a^2 b^2 (61 A-3 C)\right ) \sin (c+d x)}{12 a^3 \left (a^2-b^2\right )^2 d \cos ^{\frac{3}{2}}(c+d x)}-\frac{b \left (35 A b^4+3 a^4 (8 A-3 C)-a^2 b^2 (65 A-3 C)\right ) \sin (c+d x)}{4 a^4 \left (a^2-b^2\right )^2 d \sqrt{\cos (c+d x)}}+\frac{\left (A b^2+a^2 C\right ) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))^2}-\frac{\left (7 A b^4-5 a^4 C-a^2 b^2 (13 A+C)\right ) \sin (c+d x)}{4 a^2 \left (a^2-b^2\right )^2 d \cos ^{\frac{3}{2}}(c+d x) (a+b \cos (c+d x))}\\ \end{align*}
Mathematica [A] time = 7.23324, size = 547, normalized size = 1.11 \[ \frac{\sqrt{\cos (c+d x)} \left (\frac{a^2 b^2 C \sin (c+d x)+A b^4 \sin (c+d x)}{2 a^3 \left (a^2-b^2\right ) (a+b \cos (c+d x))^2}+\frac{17 a^2 A b^4 \sin (c+d x)-3 a^2 b^4 C \sin (c+d x)+9 a^4 b^2 C \sin (c+d x)-11 A b^6 \sin (c+d x)}{4 a^4 \left (a^2-b^2\right )^2 (a+b \cos (c+d x))}-\frac{6 A b \tan (c+d x)}{a^4}+\frac{2 A \tan (c+d x) \sec (c+d x)}{3 a^3}\right )}{d}+\frac{\frac{2 \left (328 a^4 A b^2-641 a^2 A b^4+16 a^6 A-57 a^4 b^2 C+27 a^2 b^4 C+48 a^6 C+315 A b^6\right ) \Pi \left (\frac{2 b}{a+b};\left .\frac{1}{2} (c+d x)\right |2\right )}{a+b}+\frac{\left (-512 a^3 A b^3+160 a^5 A b+24 a^3 b^3 C-96 a^5 b C+280 a A b^5\right ) \left (2 F\left (\left .\frac{1}{2} (c+d x)\right |2\right )-\frac{2 a \Pi \left (\frac{2 b}{a+b};\left .\frac{1}{2} (c+d x)\right |2\right )}{a+b}\right )}{b}+\frac{2 \left (-195 a^2 A b^4+72 a^4 A b^2+9 a^2 b^4 C-27 a^4 b^2 C+105 A b^6\right ) \sin (c+d x) \cos (2 (c+d x)) \left (\left (2 a^2-b^2\right ) \Pi \left (-\frac{b}{a};\left .-\sin ^{-1}\left (\sqrt{\cos (c+d x)}\right )\right |-1\right )+2 a (a+b) F\left (\left .\sin ^{-1}\left (\sqrt{\cos (c+d x)}\right )\right |-1\right )-2 a b E\left (\left .\sin ^{-1}\left (\sqrt{\cos (c+d x)}\right )\right |-1\right )\right )}{a b^2 \sqrt{1-\cos ^2(c+d x)} \left (2 \cos ^2(c+d x)-1\right )}}{48 a^4 d (a-b)^2 (a+b)^2} \]
Antiderivative was successfully verified.
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Maple [B] time = 3.81, size = 2140, normalized size = 4.3 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{C \cos \left (d x + c\right )^{2} + A}{{\left (b \cos \left (d x + c\right ) + a\right )}^{3} \cos \left (d x + c\right )^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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